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4^(2x+1)=32/8^(x-1)
We move all terms to the left:
4^(2x+1)-(32/8^(x-1))=0
Domain of the equation: 8^(x-1))!=0We multiply all the terms by the denominator
x∈R
(4^(2x+1))*8^(x-1))-(32=0
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